Timeline for If $2^x $and $3^x$ are integers, must $x$ be as well?
Current License: CC BY-SA 2.5
6 events
| when toggle format | what | by | license | comment | |
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| May 2, 2010 at 1:50 | comment | added | Victor Miller | I'll confess that I was the one that brought it up on the NMBRTHRY list. After it was pointed out that it was the six exponentials theorem, I made a big "duh", since Lang was my advisor when he proved the above referenced result, and I knew about then. | |
| Mar 9, 2010 at 19:00 | comment | added | Kevin Buzzard | Oh, "arithmetic" means "n^x for all n", but in the proof that arithmetic implies algebraic he only uses finitely many n. | |
| Mar 9, 2010 at 18:42 | comment | added | Alon Amit | Very interesting! Just to make sure I understand - does this generalize the "n^x for all n" version only, or can it be applied to "2,3,5" and "2,3" as well? | |
| Mar 9, 2010 at 9:57 | history | edited | Kevin Buzzard | CC BY-SA 2.5 |
mild logical fix
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| Mar 9, 2010 at 8:34 | history | edited | Kevin Buzzard | CC BY-SA 2.5 |
fixed typo
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| Mar 9, 2010 at 7:58 | history | answered | Kevin Buzzard | CC BY-SA 2.5 |