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Jul 11, 2014 at 10:10 comment added user75691 That's perfect. Thank you again for your time and for your help.
Jul 10, 2014 at 20:59 comment added HJRW Yes, the 'finite-sheeted' condition means algebraically that the restriction to each vertex group is finite-index.
Jul 10, 2014 at 15:15 comment added user75691 Yes, I understand. We just need to put some conditions in vertex groups/spaces. I have a final question if this is possible, this condition for example corresponds algebraically to finite index, I mean something like this is enough? I would like to thank both of you, for your answers, they are very helpful for me.
Jul 10, 2014 at 13:10 comment added HJRW Yes, as @BenjaminSteinberg says, finite Kurosh rank is enough, but you need the 'finite-sheeted' hypothesis.
Jul 10, 2014 at 11:45 comment added Benjamin Steinberg But you would need to interpret finite sheeted relative to vertex groups.
Jul 10, 2014 at 11:39 comment added Benjamin Steinberg Finite Kurosh rank should be enough. It is sufficient for the argument in my paper. You basically need a finite core of some sort.
Jul 10, 2014 at 10:31 comment added user75691 I am asking this question because in the case of graph of groups it is enough to suppose finite Kurosh rank which implies finite graph of groups.
Jul 10, 2014 at 9:57 comment added user75691 Thanks a lot both of for your answers. This theorem is very similar to that I want. Can I ask you something? I would like to ask if we need the hypothesis of finitely generated, because we want that every vertex space to be finite?
Jul 10, 2014 at 9:56 vote accept user75691
Jul 9, 2014 at 21:09 comment added HJRW @BenjaminSteinberg, well, I've added a rough definition. I can't define it formally without recalling the definition of graphs of spaces etc.
Jul 9, 2014 at 21:08 history edited HJRW CC BY-SA 3.0
Added rough definition of a precovering.
Jul 9, 2014 at 20:58 comment added Benjamin Steinberg @HRJW, perhaps you should define a precovering?
Jul 9, 2014 at 20:46 comment added HJRW @BenjaminSteinberg - no, it's all bound up in the definition of a precovering!
Jul 9, 2014 at 19:53 comment added Benjamin Steinberg @HRJW, you need some separability hypotheses here don't you?
Jul 9, 2014 at 19:48 history answered HJRW CC BY-SA 3.0