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Jul 7, 2014 at 18:35 vote accept Hyperbolic Asker
Jul 6, 2014 at 18:19 answer added Greg Stevenson timeline score: 6
Jul 6, 2014 at 6:21 answer added Karol Szumiło timeline score: 9
Jul 6, 2014 at 3:07 comment added Eric Wofsey I expect this is usually false. For instance, $D(S)$ always has a compact generator, and it seems unlikely that $K(R)$ does (except maybe if $R$ is Artinian or some condition of that sort). Indeed, it's not clear to me that $K(\mathbb{Z})$ even has a set of generators, though I don't have very strong intuition for this.
Jul 5, 2014 at 23:33 review First posts
Jul 5, 2014 at 23:40
Jul 5, 2014 at 23:12 history asked Hyperbolic Asker CC BY-SA 3.0