Timeline for Can you "Wedge" two representations?
Current License: CC BY-SA 3.0
12 events
when toggle format | what | by | license | comment | |
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Jun 15, 2020 at 7:27 | history | edited | CommunityBot |
Commonmark migration
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Oct 10, 2013 at 22:19 | answer | added | Vít Tuček | timeline score: 0 | |
S Oct 10, 2013 at 18:40 | history | suggested | Matthew Pressland | CC BY-SA 3.0 |
Fixed old LaTeX workaround (stumbled upon the page, won't be bumping lots of questions).
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Oct 10, 2013 at 18:35 | review | Suggested edits | |||
S Oct 10, 2013 at 18:40 | |||||
Mar 7, 2010 at 19:23 | history | edited | john mangual | CC BY-SA 2.5 |
More detail...
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Mar 7, 2010 at 14:59 | comment | added | Mariano Suárez-Álvarez | What are you trying to achieve by the putative wedge product? Answering that first is the first step in order to see if there is an operation which does what you want... | |
Mar 7, 2010 at 6:57 | answer | added | Douglas Zare | timeline score: 3 | |
Mar 7, 2010 at 0:52 | answer | added | darij grinberg | timeline score: 11 | |
Mar 7, 2010 at 0:45 | answer | added | Marty | timeline score: 11 | |
Mar 7, 2010 at 0:36 | comment | added | Tom Church | Not all Schur functors can be obtained just from symmetric products and wedge products; rather Schur functors generalize the definition of Sym^k V and /\^k V as the elements in Tensor^k V which transform in a certain way under permutation of the factors. | |
Mar 7, 2010 at 0:21 | comment | added | José Figueroa-O'Farrill | I think you've answered your own question. You cannot. The Wedge is just the alternation (if that is word) of the tensor product, which is the sign representation of the symmetric group $S_2$ acting on $V \otimes V$. There is no action of the symmetric group on $V \otimes W$. | |
Mar 7, 2010 at 0:11 | history | asked | john mangual | CC BY-SA 2.5 |