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Jun 15, 2020 at 7:27 history edited CommunityBot
Commonmark migration
Oct 10, 2013 at 22:19 answer added Vít Tuček timeline score: 0
S Oct 10, 2013 at 18:40 history suggested Matthew Pressland CC BY-SA 3.0
Fixed old LaTeX workaround (stumbled upon the page, won't be bumping lots of questions).
Oct 10, 2013 at 18:35 review Suggested edits
S Oct 10, 2013 at 18:40
Mar 7, 2010 at 19:23 history edited john mangual CC BY-SA 2.5
More detail...
Mar 7, 2010 at 14:59 comment added Mariano Suárez-Álvarez What are you trying to achieve by the putative wedge product? Answering that first is the first step in order to see if there is an operation which does what you want...
Mar 7, 2010 at 6:57 answer added Douglas Zare timeline score: 3
Mar 7, 2010 at 0:52 answer added darij grinberg timeline score: 11
Mar 7, 2010 at 0:45 answer added Marty timeline score: 11
Mar 7, 2010 at 0:36 comment added Tom Church Not all Schur functors can be obtained just from symmetric products and wedge products; rather Schur functors generalize the definition of Sym^k V and /\^k V as the elements in Tensor^k V which transform in a certain way under permutation of the factors.
Mar 7, 2010 at 0:21 comment added José Figueroa-O'Farrill I think you've answered your own question. You cannot. The Wedge is just the alternation (if that is word) of the tensor product, which is the sign representation of the symmetric group $S_2$ acting on $V \otimes V$. There is no action of the symmetric group on $V \otimes W$.
Mar 7, 2010 at 0:11 history asked john mangual CC BY-SA 2.5