Timeline for Functions that Calculate their $L_p$ Norm
Current License: CC BY-SA 3.0
12 events
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| Jul 4, 2014 at 4:50 | comment | added | Christian Remling | @AthanagorWurlitzer: No problem, of course. As for the remaining case, I don't really have a good idea right now, but I have a feeling that one has to study $f$ near $b$ rather carefully; just Holder feels too "soft." | |
| Jul 3, 2014 at 16:48 | comment | added | Christian Remling | @AthanagorWurlitzer: I don't think restricting to a subinterval will work since $\|f\|_{L^p(c,d)}<\|f\|_{L^p(a,b)}$, so the restricted $f$ will no longer satisfy the equation you're trying to solve. | |
| Jul 3, 2014 at 10:46 | comment | added | username | Considering continuous functions on $(a,b)$ (as they must be), you excluded all cases, $b-a>1$, $b-a=1$ and $b-a<1$. The interval being bounded, can't you remove the last case by just considering $(c,d)\subset(a,b)$? | |
| Jul 3, 2014 at 5:13 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jul 3, 2014 at 5:08 | history | undeleted | Christian Remling | ||
| Jul 3, 2014 at 5:08 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jul 3, 2014 at 0:15 | history | deleted | Christian Remling | via Vote | |
| Jul 3, 2014 at 0:11 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jul 2, 2014 at 23:54 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jul 2, 2014 at 23:50 | history | undeleted | Christian Remling | ||
| Jul 2, 2014 at 23:49 | history | deleted | Christian Remling | via Vote | |
| Jul 2, 2014 at 23:48 | history | answered | Christian Remling | CC BY-SA 3.0 |