Timeline for What is the fundamental group of a hypersurface?
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Jul 2, 2014 at 10:10 | vote | accept | Alex Gavrilov | ||
Jul 2, 2014 at 8:51 | comment | added | abx | Even if it is only birationally equivalent, its $\pi_1$ is isomorphic to that of $S$, hence is arbitrary. | |
Jul 2, 2014 at 6:52 | comment | added | Alex Gavrilov | You are probably right. But I am not sure I understand why the strict transform is isomorphic to $S$, not only birationally equivalent. | |
Jul 2, 2014 at 6:35 | history | answered | abx | CC BY-SA 3.0 |