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Apr 16, 2020 at 5:55 vote accept David C
Apr 16, 2020 at 2:24 answer added Jianbo Wang timeline score: 3
Jul 4, 2014 at 5:04 comment added roy smith I suggest asking Bob Friedman.
Jul 3, 2014 at 21:57 history edited David C CC BY-SA 3.0
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Jul 2, 2014 at 13:56 history edited Daniel Loughran CC BY-SA 3.0
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Jul 2, 2014 at 9:17 comment added nsrt Thom's result follows from the simple fact that it is a certain projective space (one coordinate for each possible coefficient in the defining polynomials) minus the Zariski closed subspace corresponding to coefficients defining singular intersections, and the latter has positive complex codimension, so real codimension > 2.
Jul 2, 2014 at 8:49 history edited David C CC BY-SA 3.0
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Jul 2, 2014 at 8:25 answer added Oscar Randal-Williams timeline score: 5
Jul 2, 2014 at 6:25 comment added David C Thank you Daniel, apparently R. Thom also proved this result thanks to purely topological arguments.
Jul 2, 2014 at 6:24 history edited David C CC BY-SA 3.0
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Jul 1, 2014 at 21:40 comment added Daniel Loughran A result of Hartshorne says that the Hilbert scheme of closed subschemes of projective space with given Hilbert polynomial is connected. Therefore it seems that any two smooth complete intersections with the same type (i.e. number and degrees of equations) are deformation equivalent (hence diffeomorphic) and so have the same Hodge numbers.
Jul 1, 2014 at 20:07 comment added Francesco Polizzi and also mathoverflow.net/questions/42709/question-about-hodge-number/…
Jul 1, 2014 at 20:06 comment added Francesco Polizzi somehow related: mathoverflow.net/questions/42744/…
Jul 1, 2014 at 19:41 history asked David C CC BY-SA 3.0