Timeline for Linear transformation of a polyhedron
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
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| Jun 25, 2018 at 15:52 | vote | accept | Mahdi - Free Palestine | ||
| Sep 10, 2016 at 0:49 | comment | added | JumpJump | Moreover, how you define $n_k^+$ and $c_k^+$? | |
| Sep 9, 2016 at 18:58 | comment | added | JumpJump | Are you definition $P(Q)$ in the way you write there of you are trying to prove $P(Q)$ has that form? Moreover, why the same $\alpha$ for all $j$? Thank you! | |
| Jun 30, 2014 at 1:22 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jun 30, 2014 at 0:13 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jun 29, 2014 at 20:16 | comment | added | Mahdi - Free Palestine | I think that for compatibiliy of the dimensions of $y$ and $n_j$, it is better to write $y\in\{e\}^\perp$ instead of $y\in \mathbb{R}^{n-1}$ in definition of $S$. | |
| Jun 29, 2014 at 15:29 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jun 29, 2014 at 15:27 | comment | added | Christian Remling | @Mahdi: Yes, $S$ is $P(Q)$, where $Q$ is the original polyhedron, defined by the constraints $x\cdot n_j\le c_j$. I'll edit. | |
| Jun 29, 2014 at 11:14 | comment | added | Mahdi - Free Palestine | For clarification your answer, Please says that $S$ is the projection of the polyhedron and defines theses notations: $n_j$, $c_j$ in your answer. | |
| Jun 29, 2014 at 10:07 | comment | added | Mahdi - Free Palestine | Thanks for your answer. Your Approach is similar to Fourier-Motzkin elimination. | |
| Jun 29, 2014 at 7:47 | history | edited | Christian Remling | CC BY-SA 3.0 |
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| Jun 29, 2014 at 7:24 | history | answered | Christian Remling | CC BY-SA 3.0 |