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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Aug 25, 2014 at 14:15 vote accept Per Alexandersson
Jun 28, 2014 at 3:29 comment added Bill Mance @Lucia oops I see. I misread it as "there are infinitely many powers of 2 with a zero in their base 10 expansion". GeraldEdgar: Lucia answered your question, but I want to add further this useful resource benfordonline.net
Jun 28, 2014 at 2:50 comment added Lucia @BillMance: Benford's law (which is simply the equidistribution of $n\log_{10} 2$ in ${\Bbb R}/{\Bbb Z}$) will tell you that given any initial pattern of digits there are many $n\le N$ with $2^n$ beginning with that pattern. It does not say anything about the decimal digits of $2^n$ for every value of $n$, which is the problem raised here (and in Gerry Myerson's comment).
Jun 28, 2014 at 2:09 comment added Gerald Edgar Reference that $2^n$ follows Benford's law?
Jun 28, 2014 at 1:39 comment added Bill Mance I might be missing something simple, but doesn't the fact that the sequence $(2^n)$ follows Benford's law in base $10$ give you some things like this?
Jun 28, 2014 at 1:34 answer added Bill Mance timeline score: 2
Jun 27, 2014 at 22:55 comment added Gerry Myerson I'm sure it's true, and I'm sure that far weaker statements are out of reach. So far as I know, there isn't even a proof that every sufficiently large power of 2 has a zero somewhere in its base-10 expression.
Jun 27, 2014 at 22:08 history asked Per Alexandersson CC BY-SA 3.0