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Jun 27, 2014 at 4:57 answer added Mike Shulman timeline score: 3
Jun 26, 2014 at 21:02 vote accept Cyrille Corpet
Jun 26, 2014 at 20:23 comment added Cyrille Corpet You're right, sorry. The restriction to contractions is only needed to have $\ell_1(\mathbb R)$ as a countable coproduct of $I=\mathbb R$.
Jun 26, 2014 at 15:00 history edited Cyrille Corpet CC BY-SA 3.0
edited title
Jun 26, 2014 at 13:14 comment added Yemon Choi @CyrilleCorpet I think the usual (projective) tensor product of Banach spaces gives you smc structure, since you still have Hom(X \otimes Y, Z) naturally iso to Hom ( X, Hom(Y,Z) )
Jun 26, 2014 at 13:07 comment added Cyrille Corpet @YemonChoi: is it really closed ? The usual closed category of Banach is the one with contracting linear maps (which has countable coproducts).
Jun 26, 2014 at 12:33 comment added Yemon Choi Could you add "with NNO" to the title of your question? (A counterexample to the question in your title, but which I think has no NNO anyway, is the category of Banach spaces and continuous linear maps between them.)
Jun 26, 2014 at 9:24 answer added Zhen Lin timeline score: 7
Jun 26, 2014 at 9:09 comment added Cyrille Corpet This definition allows to define sequences in $X$ by recursion: given a first "element" $1\to X$ and a "recursion law" $X\to X$, it defines a sequence $N\to N$. Nicer properties are given by the symmetric closed structure, for instance, addition is given as a map $N\otimes N\to N$ which is defined by adjunction by a map $N\to \operatorname{Hom}(N,N)$, itself defined by the usual recursive definition in $\operatorname{\mathbf{Set}}$.
Jun 26, 2014 at 9:03 history edited Cyrille Corpet CC BY-SA 3.0
added 19 characters in body
Jun 26, 2014 at 8:59 comment added Fernando Muro I don't get your definition of NNO. It looks like incomplete.
Jun 26, 2014 at 8:24 history edited Cyrille Corpet CC BY-SA 3.0
added 111 characters in body
Jun 26, 2014 at 8:23 comment added Cyrille Corpet Actually, I would like a category where a Natural Number Object could exist. I have edited my question accordingly.
Jun 26, 2014 at 8:14 comment added Zhen Lin Trivial example: the category of finite sets with the cartesian product...
Jun 26, 2014 at 8:04 history asked Cyrille Corpet CC BY-SA 3.0