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Mar 7, 2010 at 5:26 vote accept Mike Hartglass
Mar 6, 2010 at 5:59 comment added Konstantin Slutsky I use separability of $X$. There is a theorem, usually attributed to von Neumann, that every measure preserving automorphisms of a separable measure algebra has a unique point realization on a standard Lebesgue space. From this existence of $B_0$ follows. By $g(B_0) \ne B_0$ I mean $\mu(g(B_0) \setminus B_0) \ne 0$, so $B_1$ has positive measure.
Mar 6, 2010 at 5:04 comment added Douglas Zare The second paragraph has some gaps. What properties of $X$ are you using to construct $B_0$, since such a set doesn't have to exist for a more general probability space? You also want $B_1$ to have positive measure. How do you ensure that?
Mar 6, 2010 at 2:27 history answered Konstantin Slutsky CC BY-SA 2.5