Timeline for A general question on nonnegative integer sequence
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 24, 2014 at 22:14 | comment | added | Greg Martin | Well, I didn't feel all that guilty :) but I still followed your good suggestion. | |
| Jun 24, 2014 at 22:14 | history | edited | Greg Martin | CC BY-SA 3.0 |
deleted 61 characters in body; Post Made Community Wiki
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| Jun 23, 2014 at 17:51 | comment | added | The Masked Avenger | At least you can edit it, give Scott's answer with attribution, and assuage your guilt by making the answer CW. | |
| Jun 23, 2014 at 17:47 | comment | added | Greg Martin | @TheMaskedAvenger: hmm, I think you're exactly right. Thanks for pointing out the error. S. Carnahan's comment on the OP seems more correct. (At least this gave me the opportunity to learn that one can't delete an accepted answer....) | |
| Jun 23, 2014 at 16:07 | comment | added | The Masked Avenger | As I read this, I get that one picks c_j and d_j and then puts into A and B integers to ensure that c_j ends up in 2A and d_j ends up in 2B. However, it is also needed for the conclusion that (something like) c_j does not end up in 2B and d_j does not end up in 2A. How do we get this guarantee? | |
| Jun 23, 2014 at 9:05 | vote | accept | Mike | ||
| Jun 23, 2014 at 8:54 | comment | added | Mike | Thanks,How about $A=\{x\ |\ x\in\mathbb Z_{\ge 0},\ x=\ $some forms$\ \}$? | |
| Jun 23, 2014 at 7:11 | history | answered | Greg Martin | CC BY-SA 3.0 |