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Jun 23, 2014 at 14:33 history edited Lucia CC BY-SA 3.0
added 12 characters in body
Jun 23, 2014 at 14:31 comment added Lucia @Glasby: Yes indeed; thanks for the correction.
Jun 23, 2014 at 11:50 vote accept Glasby
Jun 23, 2014 at 8:01 comment added Glasby Thanks Gerhard and Lucia. I think you want $D(p^k)=(-1)^k2$ for $p\equiv 3\pmod 4$. D.H. Lehmer's paper is nice: my proofs are simpler but less general too.
Jun 22, 2014 at 14:19 history answered Lucia CC BY-SA 3.0