Timeline for Finding a suitable number
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 23, 2014 at 15:03 | vote | accept | Tina | ||
| Jun 23, 2014 at 13:41 | history | edited | Stefan Kohl♦ | CC BY-SA 3.0 |
Corrected and extended list of examples.
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| Jun 23, 2014 at 11:32 | comment | added | Tina | Dear Stefan Kohl, thank you so much for your answer. Actually, I am working on alternating groups and in all your examples $q^2\nmid n!/m!$. My proofs works for these cases. So, I have to edit my question again. By the way, if $n=1342$ and $m=1327$, then $q=443$ and not $q=269$. | |
| Jun 23, 2014 at 10:23 | vote | accept | Tina | ||
| Jun 23, 2014 at 11:18 | |||||
| Jun 21, 2014 at 20:51 | history | answered | Stefan Kohl♦ | CC BY-SA 3.0 |