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Jun 26, 2014 at 21:49 vote accept student
Jun 26, 2014 at 21:48 vote accept student
Jun 26, 2014 at 21:49
Jun 19, 2014 at 17:01 answer added Christian Remling timeline score: 6
Jun 19, 2014 at 13:27 answer added Carlo Beenakker timeline score: 1
Jun 19, 2014 at 1:38 comment added student @ChristianRemling If the boundary condition is $Bu|_{\partial U} = g, g$ non-zero, then $u(t, x) = 0$ will not even solve the wave equation. As far as I can see, the boundary condition matters.
Jun 19, 2014 at 1:36 history edited student CC BY-SA 3.0
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Jun 19, 2014 at 0:55 comment added student @ChristianRemling I am not sure that the local derivation works always. For example, consider the boundary condition $Bu|_{\partial U} = g$, $g$ non-zero. Here the solution has to have infinite speed of propagation necessarily. I feel that the usual proof works fine up to the Dirichlet or Neumann condition, but not sure about other boundary conditions.
Jun 18, 2014 at 23:25 review First posts
Jun 19, 2014 at 0:25
Jun 18, 2014 at 23:17 comment added Christian Remling I don't see how a boundary condition would help you. You can show finite propagation speed locally, with an energy estimate.
Jun 18, 2014 at 23:06 history asked student CC BY-SA 3.0