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Jun 19, 2014 at 5:04 comment added Kevin Ventullo Hmm, yeah that was nonsense. Not sure what I was thinking
Jun 18, 2014 at 22:18 comment added fedja @Kevin Ventullo I guess I know how to derive a few things like Riemann Hypothesis (or its negation, if you prefer) from the inequality you wrote (the most likely reason is, of course, that you meant something completely different and your fingers just slipped on the keypad when typing :-))
Jun 18, 2014 at 12:43 comment added timur If the dimension of the Hilbert space is infinite, you can find a vector whose expansion converges with the error going to $0$ slower than any prescribed function that goes to $0$, even in the orthogonal basis setting. However, useful things can be said depending on the particular situation. For example, if your space $X$ is $L^2$, and the basis elements $V_k$ are some kind of piecewise polynomials, then the convergence is faster for smoother functions.
Jun 18, 2014 at 8:41 comment added Yuriy M well ok, this assumes we know $a_k$, but the situation we have is that we have $X$ and $\{V_k\}$. Since in nonorthogonal case finding $a_k$'s requires solving a system of general linear equation, we can't get much information about the behavior of $a_k$. Perhaps I should have said, are there any known results about convergence that rely on the properties of $X$ and $\{V_k\}$.
Jun 18, 2014 at 8:18 review First posts
Jun 18, 2014 at 8:26
S Jun 18, 2014 at 8:18 history suggested Loïc Teyssier CC BY-SA 3.0
Latexed and removed non-relevant introductory sentence
Jun 18, 2014 at 8:14 review Suggested edits
S Jun 18, 2014 at 8:18
S Jun 18, 2014 at 8:13 history suggested leo monsaingeon CC BY-SA 3.0
LaTeX formatting fixed
Jun 18, 2014 at 8:08 review Suggested edits
S Jun 18, 2014 at 8:13
Jun 18, 2014 at 8:07 comment added leo monsaingeon You may want to use LaTeX formatting (just use the usual $symbols) for a better diplay next time...
Jun 18, 2014 at 8:00 history asked Yuriy M CC BY-SA 3.0