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Jun 10, 2011 at 3:59 comment added Junkie The latest Magma does this trivially in 0.6s and 25MB, so they must have improved it.
Dec 16, 2010 at 22:40 answer added Lubin timeline score: 38
Mar 6, 2010 at 20:24 vote accept Kevin Buzzard
Mar 6, 2010 at 10:04 answer added David Loeffler timeline score: 29
Mar 5, 2010 at 22:37 comment added moonface Quick ad hoc calculation (not checked): standard permutation representation of D_8 on a square gives a 4-dimensional linear representation, which is the sum of a trivial representation, the representation you want, and a quadratic character. The discriminant of the associated quartic field is (at 2) of valuation 10, so you just need to figure out what the associated quadratic field is; I think (without checking) it's $\mathbb{Q}(\sqrt{2})$, so that gives 7. Did that very hastily, though, don't trust i
Mar 5, 2010 at 20:32 comment added Kevin Buzzard Somehow I suspect (although I didn't check) that although you are right, these limitations will somehow be built in to the standard limitations on the jumps explained in e.g. Serre's local fields book.
Mar 5, 2010 at 20:12 answer added dke timeline score: 9
Mar 5, 2010 at 19:58 comment added Marty Have you considered the constraints imposed by the integrality of the Artin conductor? For 2-dimensional Galois representations of dihedral type, I'd think this would limit the possibilities for higher ramification groups.
Mar 5, 2010 at 19:34 history asked Kevin Buzzard CC BY-SA 2.5