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There is no useful closed-form for this. You can write it down as $$2^N - \binomial{N}{k+1} {}_2F_{1}(1, k+1-N, k+2; -1)$$$$2^N - \binom{N}{k+1} {}_2F_{1}(1, k+1-N, k+2; -1)$$ but that's really just a rewrite of the sum in a different form.

There is no useful closed-form for this. You can write it down as $$2^N - \binomial{N}{k+1} {}_2F_{1}(1, k+1-N, k+2; -1)$$ but that's really just a rewrite of the sum in a different form.

There is no useful closed-form for this. You can write it down as $$2^N - \binom{N}{k+1} {}_2F_{1}(1, k+1-N, k+2; -1)$$ but that's really just a rewrite of the sum in a different form.

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Jacques Carette
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There is no useful closed-form for this. You can write it down as $$2^N - \binomial{N}{k+1} {}_2F_{1}(1, k+1-N, k+2; -1)$$ but that's really just a rewrite of the sum in a different form.