Timeline for Is there a nice way to write the generating function obtained by taking the quadratic coefficients of another one?
Current License: CC BY-SA 3.0
9 events
| when toggle format | what | by | license | comment | |
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| Jun 15, 2014 at 4:11 | answer | added | S. Carnahan♦ | timeline score: 4 | |
| S Jun 15, 2014 at 2:24 | history | suggested | Jeremy Rouse |
Added modular forms tag
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| Jun 15, 2014 at 2:08 | review | Suggested edits | |||
| S Jun 15, 2014 at 2:24 | |||||
| Jun 14, 2014 at 18:22 | history | edited | Simon Rose | CC BY-SA 3.0 |
Added more specificity.
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| Jun 14, 2014 at 18:20 | comment | added | Simon Rose | Considering @QiaochuYuan's comment, I perhaps should have been more specific about this question, since it seems that there is no way that this will hold in full generality. | |
| Jun 13, 2014 at 12:52 | comment | added | Jeremy Rouse | Related to the previous comment, if your generating function is a half-integer weight modular form, then the index $t$ Shimura lift will output an integer-weight modular form whose Fourier coefficients involve the numbers $a_{tk^{2}}$. It's hard to know if this is applicable without knowing where your $g(q)$ comes from. | |
| Jun 13, 2014 at 0:21 | comment | added | S. Carnahan♦ | Sometimes you can pull this out of a theta lift, e.g., if you happen to have a weight 1/2 form. See mathoverflow.net/questions/159189/… for an example. | |
| Jun 12, 2014 at 23:17 | comment | added | Qiaochu Yuan | I don't see any reason the result should be nice in general. Consider, for example, the case $a_k = \frac{1}{k!}$. | |
| Jun 12, 2014 at 23:09 | history | asked | Simon Rose | CC BY-SA 3.0 |