Skip to main content
11 events
when toggle format what by license comment
Nov 21 at 5:04 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jul 24 at 5:03 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Mar 26 at 4:57 comment added Willie Wong I don't think the question being asked makes sense. You are treating $u$ as an $L^2$ valued function, then you cannot plug $u$ into $f$, which has domain $\mathbb{R}$. Perhaps you meant to think about $u$ as a space-time function, and $f$ as really acting on the final output. But then it is not compatible with the form of the chain rule you are suggesting. (In fact, if the spatial domain is non-compact, and $f(0) \neq 0$, you don't even have $f(u)$ is an element of $L^2(0,T;L^2)$.) So I think the first thing is to for you to think about and specify what exactly is this object $f(u)$.
Mar 26 at 4:07 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Nov 27, 2023 at 4:07 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jul 30, 2023 at 3:11 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Apr 1, 2023 at 3:05 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Dec 2, 2022 at 2:08 history bumped CommunityBot This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.
Jun 13, 2014 at 12:50 answer added k3thomps timeline score: 0
Jun 12, 2014 at 20:55 review First posts
Jun 12, 2014 at 20:57
Jun 12, 2014 at 20:40 history asked mathias_l CC BY-SA 3.0