Skip to main content
MathOverflow

Return to Question

added 63 characters in body
Source Link
user5262
user5262
  • 113
  • 4

Let $S = Spec(O_K)$ be the spectrum of the rings of integers of a number field $K$. Let $A/S$$A/S \setminus T$ be an Abelian scheme over an open subscheme $S \setminus T \subseteq S$. Does the kernel of $n$-multiplication $A[n]$ become constant after a (non empty) étale base change $S' \to S \setminus \{x_1,\ldots,x_n\}$?

Let $S = Spec(O_K)$ be the spectrum of the rings of integers of a number field $K$. Let $A/S$ be an Abelian scheme. Does the kernel of $n$-multiplication $A[n]$ become constant after a (non empty) étale base change $S' \to S \setminus \{x_1,\ldots,x_n\}$?

Let $S = Spec(O_K)$ be the spectrum of the rings of integers of a number field $K$. Let $A/S \setminus T$ be an Abelian scheme over an open subscheme $S \setminus T \subseteq S$. Does the kernel of $n$-multiplication $A[n]$ become constant after a (non empty) étale base change $S' \to S \setminus \{x_1,\ldots,x_n\}$?

Source Link
user5262
user5262
  • 113
  • 4

kernel of isogeny becomes constant after base change

Let $S = Spec(O_K)$ be the spectrum of the rings of integers of a number field $K$. Let $A/S$ be an Abelian scheme. Does the kernel of $n$-multiplication $A[n]$ become constant after a (non empty) étale base change $S' \to S \setminus \{x_1,\ldots,x_n\}$?