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Timeline for Divisibility in homology/homotopy

Current License: CC BY-SA 3.0

11 events
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Jun 10, 2014 at 17:43 comment added Jesse C. McKeown OK, nifty! ... but... why are those comments and not answers? But thanks, both.
Jun 10, 2014 at 11:46 comment added Tom Goodwillie Duplicating what Achim Krause said somewhat: Any suspension has all homology primitive, but you can attach an $(n+4)$-cell to $S^n$ for large $n$ by a map that generates a summand of order three in the homotopy group.
Jun 10, 2014 at 6:45 comment added Achim Krause The cone of any element in the homotopy groups of spheres which is not detected by the Hopf invariant will even have primitive homology. Pick any of those which is not divisible by p, and you have a counterexample, if I understand your question correctly.
Jun 10, 2014 at 4:46 history edited Jesse C. McKeown CC BY-SA 3.0
acknowledging ambiguity in representatives of presented things
Jun 10, 2014 at 4:44 comment added Jesse C. McKeown Then I should ask if they can be chosen divisible by $p$. OK.
Jun 10, 2014 at 0:20 comment added Tom Goodwillie I don't know what "the cellular attaching maps are divisible by $p$" means. The same space can have more than one cell structure.
Jun 9, 2014 at 23:17 comment added Jesse C. McKeown I can also tell you exactly what the particular complex is I have in mind, but that might defeat the purpose.
Jun 9, 2014 at 23:16 history edited Jesse C. McKeown CC BY-SA 3.0
clarified ambiguous notation
Jun 9, 2014 at 23:10 comment added Jesse C. McKeown Here, $x$ is meant to be a homology class, though for my particular complex it could as easily be a chain --- but then I'd have to check the comultiplication again. If mathoverflow will let me, I'll adjust the question.
Jun 9, 2014 at 22:17 comment added Tom Goodwillie Is $x$ a chain or a homology class? Can you ask the question more precisely?
Jun 9, 2014 at 19:17 history asked Jesse C. McKeown CC BY-SA 3.0