Timeline for Is there an additive model of the stable homotopy category?
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
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| Jul 23, 2022 at 8:39 | history | edited | Martin Sleziak | CC BY-SA 4.0 |
http -> https (the question was bumped anyway)
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| S Jul 23, 2022 at 7:40 | history | suggested | Amartya | CC BY-SA 4.0 |
Links to papers referenced fixed
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| Jul 23, 2022 at 5:14 | review | Suggested edits | |||
| S Jul 23, 2022 at 7:40 | |||||
| Dec 13, 2011 at 20:48 | history | edited | Mike Shulman | CC BY-SA 3.0 |
added a couple missing words
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| Mar 6, 2010 at 1:47 | history | edited | D.-C. Cisinski | CC BY-SA 2.5 |
fixed spelling and grammar
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| Mar 4, 2010 at 11:59 | comment | added | D.-C. Cisinski | Yes, you are right. We have to require the equivalence Ho(C)=S to be compatible with the triangulated structures. | |
| Mar 4, 2010 at 8:33 | vote | accept | Don Stanley | ||
| Mar 4, 2010 at 3:14 | comment | added | Tyler Lawson | A nice answer. One question: doesn't Schwede's rigidity result require Ho(C) to be triangulated equivalent to the stable homotopy category, rather than merely an equivalent category? (Perhaps this is something the OP is willing to assume.) | |
| Mar 4, 2010 at 0:57 | comment | added | Harry Gindi | This is one of the best answers I've ever seen on MO. | |
| Mar 4, 2010 at 0:55 | history | answered | D.-C. Cisinski | CC BY-SA 2.5 |