Timeline for An example where GCD depends on the domain
Current License: CC BY-SA 2.5
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Mar 3, 2010 at 4:51 | vote | accept | Alfonso Gracia-Saz | ||
| Mar 3, 2010 at 2:35 | history | edited | t3suji | CC BY-SA 2.5 |
added another example
|
| Mar 2, 2010 at 22:41 | history | edited | t3suji | CC BY-SA 2.5 |
changed example with lcm to gcd
|
| Mar 2, 2010 at 22:39 | comment | added | t3suji | @Johannes Hahn: Oops, I just hate these abbreviations :) Thanks, I'll fix it. | |
| Mar 2, 2010 at 20:59 | comment | added | Paul Yuryev | Isn't S isomorphic to k[x,y]? (in which case it is even a UFD) | |
| Mar 2, 2010 at 20:18 | comment | added | Alfonso Gracia-Saz | Duh. That seems to work. Is $S$ a GCD-domain as well? | |
| Mar 2, 2010 at 19:48 | comment | added | Johannes Hahn | You're computing the lcm and not the gcd. But the example works for these too: $gcd_R(a,b)=v$ and $gcd_S(a,b)=1$. | |
| Mar 2, 2010 at 19:35 | history | answered | t3suji | CC BY-SA 2.5 |