Timeline for Smooth function over a manifold into an algebra
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Jun 3, 2014 at 12:01 | comment | added | Jochen Wengenroth | Since $C^\infty(M)$ is a nuclear Frechet space you can choose more or less any of the usual tensor topologies (like the projective $\pi$ or the injective $\varepsilon$) and you get $C^\infty(M,A)\cong C^\infty(M) \tilde{\otimes} A$ (the completed tensor product) for all Banach (or Frechet) spaces $A$. | |
Jun 3, 2014 at 11:18 | review | First posts | |||
Jun 3, 2014 at 11:27 | |||||
Jun 3, 2014 at 11:12 | comment | added | Igor Khavkine | If $A$ is finite dimensional, this is trivial (pick a basis for $A$). If not, then you need to be more specific on the conditions you agree to on $A$ (topology, etc.). | |
Jun 3, 2014 at 10:59 | history | asked | nielzs | CC BY-SA 3.0 |