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Jun 3, 2014 at 2:30 comment added Shivam Patel @Lucia sorry ..I did not see the list ...just as a curiosity so can you tell me the distribution of numbers in form $10n$ in the sequence
Jun 3, 2014 at 2:28 comment added Lucia @ShivamPatel: Not true -- $810$, $840$, $960$ etc. I'm afraid I don't know any more about this sequence!
Jun 3, 2014 at 2:26 comment added Shivam Patel @Lucia can you prove that if the number in the list is in the form $15n$ then $n$ is a prime.
Jun 3, 2014 at 2:25 comment added Shivam Patel @Lucia extremely good proof
Jun 3, 2014 at 2:16 comment added Lucia Here is a variant of your construction which produces many excluded numbers. I claim that if $p$ (a prime) is large then $15p$ fails the conjecture. For if $n=15pd(n)$ and $p$ is large then $p$ can divide $n$ only to the power $1$ (use $d(n)\le n^{1/3}$ for large $n$). If now $n=pm$ with $(p,m)=1$ then we must have $m=30d(m)$, contradicting Greg Martin's result that $30$ is excluded. In fact, inspecting his table it looks like $15p$ is excluded for all primes $p>5$.
Jun 2, 2014 at 21:40 history edited Tony Huynh CC BY-SA 3.0
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Jun 2, 2014 at 21:27 history edited Tony Huynh CC BY-SA 3.0
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Jun 2, 2014 at 20:13 history answered Tony Huynh CC BY-SA 3.0