Timeline for A non-linear PDE
Current License: CC BY-SA 3.0
12 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 3, 2014 at 0:57 | comment | added | k3thomps | @michael thank you for your patience. I was being stupid. | |
| Jun 2, 2014 at 21:57 | comment | added | k3thomps | @renardy Ahhh, you are right. Sorry. | |
| Jun 2, 2014 at 21:44 | answer | added | Michael Renardy | timeline score: 3 | |
| Jun 2, 2014 at 21:37 | comment | added | Michael Renardy | @k3thomps: No. According to the equation, we have $\partial_{tx}u=-(1-u)^n=-1^n=-1$. The conditions imposed are compatible. | |
| Jun 2, 2014 at 19:45 | comment | added | guest | No - it's coming from the calculation of a combinatorial generating function. A change of variables does make this a non-linear wave equation, but as far as I know (and I hope I'm wrong!) it isn't one that has been solved so I'm not sure how much that helps. | |
| Jun 2, 2014 at 19:14 | comment | added | k3thomps | Ummm.. This is just the wave equation in 2d in null coordinates with nonlinearity $-(1-u)^n$. Is that where you got it from? | |
| Jun 2, 2014 at 19:13 | comment | added | guest | It was a typo - thanks for catching it. | |
| Jun 2, 2014 at 19:12 | history | edited | guest | CC BY-SA 3.0 |
Corrected Type
|
| Jun 2, 2014 at 19:05 | comment | added | leo monsaingeon | Quite unlikely, indeed... Thanks Michael Renardy for pointing that out. Is there a typo, or should we close? | |
| Jun 2, 2014 at 18:55 | comment | added | Michael Renardy | How can you have $u(x,0)=0$ and $u_x(x,0)=1-x$? | |
| Jun 2, 2014 at 18:53 | comment | added | leo monsaingeon | what about power series in $t,(x-1)$? but you're missing anyway a boundary condition at $x\to\infty$... | |
| Jun 2, 2014 at 18:42 | history | asked | guest | CC BY-SA 3.0 |