Timeline for Dimension of image of a hyperplane section
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
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| Jun 2, 2014 at 13:24 | comment | added | user39380 | Thanks，but there is still a point unclear to me: suppose $X\subset \mathbb{P}(V)$, for each $u$, we can choose a general $H$ such that $\text{dim}{H\cap f^{-1}(u)}=n-m-1$, that means: $\text{dim}{H\cap f^{-1}(u)}=n-m-1$ holds for $H$ in a Zariski dense subset $U_u\subset \mathbb{P}（V^*)$.But now we hope $f|_{X\cap_H}$ have fiber of dimension $n-m-1$ on a open set of $T=f(X\cap H)$, so we ask $H \in \cap_{u\in T}{U_u}$, why does this intersection contain a open subset set?（As we hope to prove for a general $H$, \text{dim}(H\cap X)=m） | |
| Jun 2, 2014 at 0:52 | vote | accept | CommunityBot | ||
| Jun 2, 2014 at 13:25 | |||||
| Jun 1, 2014 at 23:43 | history | answered | Sasha Anan'in | CC BY-SA 3.0 |