Timeline for Conjecture about a sequence of natural numbers, such that, $\forall n : A_n<P_n<A_{n+1}$
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 9, 2015 at 21:37 | vote | accept | barak manos | ||
| Jun 2, 2014 at 8:24 | comment | added | Greg Martin | yep that's right | |
| Jun 2, 2014 at 6:13 | comment | added | barak manos | Hmmmm... I assume that the conjecture you state in your answer has not been proved, otherwise it would imply that there are an infinite number of pairs of twin primes (which I know for sure has not been proved)... right? | |
| Jun 2, 2014 at 4:58 | comment | added | Greg Martin | Right: I said "whenever $P_n$ is one of these $6k+1$ primes", meaning corresponding to a $k$ for which $k,6k-1,6k+1$ are all prime as in the prior sentence. | |
| Jun 2, 2014 at 4:46 | comment | added | barak manos | Thanks, but I don't understand the statement "Whenever $P_n$ is one of these $6k+1$ primes, you're forced to take $A_n=6k$". For example, let $P_n=79=6\cdot13+1$. You're suggesting that I must take $A_n=78$, but according to my definition, I can take $A_n$ to be any of the following numbers - $74,75,76,77,78$. Your suggestion holds only when $P_n$ is one of two twin primes. | |
| Jun 1, 2014 at 22:28 | history | answered | Greg Martin | CC BY-SA 3.0 |