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May 30, 2014 at 0:58 comment added Otis Chodosh I could be wrong, but I think that at this stage, either choice would be fine. I'd guess there is just some reason that the other way is more convenient.
May 30, 2014 at 0:02 comment added Slm2004 The projection map is still not natural for me. Why we can not project like this way: $\Pi f=\sum_{a\not\in A}\left(\int_Mu_\infty^{\frac{4}{n-2}}\psi_a fd\mu_0\right)\psi_a$, which is the projection with respect to the inner product $()_\infty$? I guess the answer is if we project this way, we get nothing
May 29, 2014 at 23:52 comment added Slm2004 I have come up this $F$ before, but not as clear as you think. Thank you very much for your explanation. @otis chodosh
May 29, 2014 at 23:49 vote accept Slm2004
May 29, 2014 at 23:05 history answered Otis Chodosh CC BY-SA 3.0