Timeline for Family of Enriques surfaces and Grothendieck-Riemann-Roch
Current License: CC BY-SA 2.5
3 events
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| Aug 25, 2010 at 13:21 | comment | added | Torsten Ekedahl | The equality $R^0f_\ast\mathcal O_Y=\mathcal O_T$ is in fact quite easy: We have a map $O_T \to R^0f_\ast\mathcal O_Y$ and if we know that the right hand side commutes with base change then by Nakayama's lemma the map is surjective and as both sides are line bundle it is an isomorphism. | |
| Mar 2, 2010 at 16:23 | history | edited | Andrea Ferretti | CC BY-SA 2.5 |
added 194 characters in body
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| Mar 2, 2010 at 13:11 | history | answered | Andrea Ferretti | CC BY-SA 2.5 |