Timeline for Growth of the truncation of the integral multiples of an irrational number
Current License: CC BY-SA 3.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 27, 2014 at 20:59 | answer | added | Robert Israel | timeline score: 1 | |
| S May 27, 2014 at 15:08 | history | suggested | user21574 | CC BY-SA 3.0 |
typo edited
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| May 27, 2014 at 15:04 | review | Suggested edits | |||
| S May 27, 2014 at 15:08 | |||||
| May 27, 2014 at 14:59 | comment | added | Willie Wong | From equidistribution $na - [na] > \frac12$ infinitely frequently. Thus for any function $f:\mathbb{N}\to\mathbb{R}$ with $\lim_{n\to\infty} f(n) = \infty$ the sequence $f(n) (na - [na])$ cannot remain bounded. But I think this is not exactly the question you asked in the final sentence. The final sentence seems to be asking about the $\liminf$ of $b^n (na - [na])$. Please edit your question to clarify. | |
| May 27, 2014 at 14:12 | review | First posts | |||
| May 27, 2014 at 15:02 | |||||
| May 27, 2014 at 13:55 | history | asked | Ángel del Río | CC BY-SA 3.0 |