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May 29, 2014 at 13:10 answer added Claudio Gorodski timeline score: 1
May 28, 2014 at 16:43 answer added Peter Michor timeline score: -1
May 28, 2014 at 14:18 answer added Misha Verbitsky timeline score: 0
S May 28, 2014 at 9:26 history suggested asv CC BY-SA 3.0
Added an update following Yves Cornulier's answer.
May 28, 2014 at 9:22 review Suggested edits
S May 28, 2014 at 9:26
May 27, 2014 at 20:09 answer added YCor timeline score: 5
S May 27, 2014 at 16:34 history suggested asv CC BY-SA 3.0
Minor corrections.
May 27, 2014 at 16:28 comment added asv I meant the former case of finitely many orbits, each locally closed. Thanks. Corrected.
May 27, 2014 at 16:25 review Suggested edits
S May 27, 2014 at 16:34
S May 27, 2014 at 16:20 history suggested asv CC BY-SA 3.0
More precise statement following the Robert Bryant's comment.
May 27, 2014 at 16:17 review Suggested edits
S May 27, 2014 at 16:20
May 27, 2014 at 15:52 comment added Robert Bryant Your question is not clear. Are you assuming that there are only finitely many orbits and that each is locally closed or that only finitely many of the orbits are locally closed. If the latter, then the answer is 'No, it is not true, even in the analytic case.' For an example, let $G =\mathbb{R}\subset\mathrm{SO}(4)$ be a connected, noncompact, $1$-parameter subgroup and let $M=S^3\subset\mathbb{R}^4$. With the obvious action of $G$ on $M$, there are only two locally closed orbits in this case, but the closure of the generic orbit is a $2$-torus.
May 27, 2014 at 11:17 history edited user51305 CC BY-SA 3.0
edited title
May 27, 2014 at 10:19 review First posts
May 27, 2014 at 10:20
May 27, 2014 at 10:13 history edited user51305 CC BY-SA 3.0
added 99 characters in body
May 27, 2014 at 10:01 history asked user51305 CC BY-SA 3.0