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May 23, 2014 at 13:54 comment added Clark T. The projection on $\mathcal{H}_{t}^{1}$ is $1 - (A(t)|_{\mathcal{H}_{t}^{1}})^{-1}A(t)$. How are you using here the Dunford integrals?
May 23, 2014 at 12:15 comment added Clark T. How can I use here Dunford integrals?
May 23, 2014 at 11:23 comment added Clark T. How does the rest follow? Could you be more specific please. Any reference?
May 23, 2014 at 10:53 comment added Michael Renardy The projection on ${\cal H}^1_t$ is differentiable as can be seen using Dunford integrals. The rest then follows.
May 23, 2014 at 7:38 review First posts
May 23, 2014 at 8:00
May 23, 2014 at 7:30 history edited Clark T. CC BY-SA 3.0
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May 23, 2014 at 7:22 history asked Clark T. CC BY-SA 3.0