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May 22, 2014 at 20:28 comment added wongpin101 Yes, it's exactly that.
May 22, 2014 at 17:56 answer added Jason Starr timeline score: 2
May 22, 2014 at 17:36 comment added Jason Starr How precisely does $P$ determine $\phi_P$? Do you mean that, via the inclusion of $C$ in $\mathbb{P}^2_K$, each point is an element of $\mathbb{P}^2_{\overline{ \mathbb{Q} }}(\overline{ \mathbb{Q} }( \mathbb{P}^2_{ \overline{ \mathbb{Q} } } ) )$, and thus induces a rational transformation $\phi_P$?
May 22, 2014 at 16:36 history asked wongpin101 CC BY-SA 3.0