Timeline for The Borel $\sigma$-algebra of the set of probability measures
Current License: CC BY-SA 4.0
8 events
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Jan 16, 2021 at 15:59 | history | edited | YCor | CC BY-SA 4.0 |
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May 25, 2014 at 11:08 | comment | added | Michael Greinecker | You can find a proof in Stochastic Optimal Control: The Discrete-Time Case by Bertsekas and Shreve, where this is Proposition 7.25. | |
May 22, 2014 at 18:24 | vote | accept | TV2323 | ||
May 22, 2014 at 1:11 | answer | added | Nate Eldredge | timeline score: 6 | |
May 22, 2014 at 0:51 | answer | added | Alexander Shamov | timeline score: 6 | |
May 22, 2014 at 0:49 | comment | added | Nate Eldredge | To show that $\mu \mapsto \mu(A)$ is measurable for every Borel $A$, try a $\pi$-$\lambda$ or monotone class argument. Let $\mathcal{L}$ be the set of all $A \subset X$ such that $\mu \mapsto \mu(A)$ is measurable, and let $\mathcal{P}$ be the closed subsets of $X$. Then it is easy to check that $\mathcal{P}$ is closed under finite intersections, $\mathcal{L}$ is a $\lambda$-system, and $\mathcal{P} \subset \mathcal{L}$. The conclusion is that $\mathcal{L} \supset \sigma(\mathcal{P})$, i.e. the Borel sets. | |
May 21, 2014 at 21:52 | review | First posts | |||
May 21, 2014 at 23:14 | |||||
May 21, 2014 at 21:34 | history | asked | TV2323 | CC BY-SA 3.0 |