Timeline for Is this groupoid a model for the derived fixed-point locus of the free loop space?
Current License: CC BY-SA 3.0
10 events
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May 22, 2014 at 0:16 | comment | added | David Roberts♦ | @AndréHenriques - it may just be that the answer is "no", or better, "no, the derived space is this: ..." | |
May 21, 2014 at 11:54 | comment | added | David Roberts♦ | Also, I gave the definition as in the Baez-Schreiber paper: your edit (replacing the dual of the wedge of the cotangent bundle with the wedge of the tangent bundle) makes this one step removed from what they actually wrote. | |
May 21, 2014 at 11:52 | comment | added | David Roberts♦ | @AndréHenriques - it's not my groupoid. A physicist told me that higher bundles over this thing should be interesting, and my guess as outlined in the post (that it is somehow the derived fixed-point locus) is the only reason I could think why. | |
May 21, 2014 at 8:17 | history | edited | André Henriques | CC BY-SA 3.0 |
removed an unnecessary double dualization.
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May 21, 2014 at 8:15 | comment | added | André Henriques | I'm not convinced that your groupoid is very interesting... Maybe a better question is: what is the derived fixed-point locus of the free loop space? -- is there a down-to-earth (i.e. finite dimensional) description of that derived space? | |
May 21, 2014 at 7:59 | comment | added | André Henriques | I thought that the derived loop space $map(S^1,M)=map((\text{cohomology of $S^1$}),M)=map((\text{odd line}),M)=\Pi TM$ is the odd tangent bundle of $M$ (the space such that functions on it are differential forms on $M$). Is that right? That doesn't look like the gerbe you describe in your first paragraph. | |
May 21, 2014 at 7:04 | history | edited | David Roberts♦ | CC BY-SA 3.0 |
added 242 characters in body
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May 21, 2014 at 7:02 | comment | added | David Roberts♦ | @AndréHenriques- well, it's in the title, but I guess I can make it more clear.<br> -Done! | |
May 21, 2014 at 7:01 | comment | added | André Henriques | Hi David. It's not quite clear what you're asking exactly. Can you be more precise? | |
May 21, 2014 at 6:58 | history | asked | David Roberts♦ | CC BY-SA 3.0 |