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May 22, 2014 at 17:39 vote accept fosco
May 21, 2014 at 11:10 comment added Giorgio Mossa I guess that for help could be useful to characterize $\star$ by universal property, otherwise is not clear what a category (not necessarily a subcategory of $\mathbf{Cat}$) closed by $\star$ should be.
May 21, 2014 at 8:18 answer added Paul Taylor timeline score: 6
May 20, 2014 at 14:36 comment added Giorgio Mossa Note that in the note you have linked Joyal define $\star B$ as a functor of type $\mathbf {Cat} \to B\setminus \mathbf {Cat}$ not $\mathbf {Cat} \to \mathbf {Cat}$.
May 20, 2014 at 14:34 comment added Giorgio Mossa The operation $\star$ does not commute with colimit: indeed if that where true then for every limit ordinal $\lambda=\bigcup_{\gamma < \lambda} \gamma$ you should have that $\lambda+1=\lambda\star[0]=\bigcup_{\gamma < \lambda} \gamma\star[0]=\bigcup_{\gamma < \lambda}\gamma+1=\lambda$ things that's not possible since $\lambda$ doesn't have a max while $\lambda+1$ does.
May 20, 2014 at 14:16 history edited fosco CC BY-SA 3.0
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May 20, 2014 at 14:01 history edited fosco CC BY-SA 3.0
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May 20, 2014 at 13:45 history asked fosco CC BY-SA 3.0