Timeline for Schreier's formula and descending chains
Current License: CC BY-SA 3.0
15 events
| when toggle format | what | by | license | comment | |
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| Apr 13, 2017 at 12:57 | history | edited | CommunityBot |
replaced http://mathoverflow.net/ with https://mathoverflow.net/
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| S Jun 8, 2014 at 13:33 | history | bounty ended | CommunityBot | ||
| S Jun 8, 2014 at 13:33 | history | notice removed | CommunityBot | ||
| S May 31, 2014 at 11:45 | history | bounty started | Pablo | ||
| S May 31, 2014 at 11:45 | history | notice added | Pablo | Draw attention | |
| May 31, 2014 at 11:23 | comment | added | Benjamin Steinberg | My proof only seems to work if the intersection of the $H_i$ is trivial. Otherwise, one needs a better argument. Sorry. | |
| May 19, 2014 at 17:10 | comment | added | Pablo | Wonderful! I will appreciate it very much. | |
| May 19, 2014 at 16:44 | comment | added | Benjamin Steinberg | I won't be able to do this for a few days because I am in the middle of final exams. If you are not sure I can try next week to write something out. | |
| May 19, 2014 at 14:44 | comment | added | Pablo | Can you give here a full argument again please? I am not sure I see how $K'$ is to be chosen. Is there any reference to a book/notes where these notions are covered? I am not sure I fully understand all the definitions. Thanks a lot!!! | |
| May 19, 2014 at 14:24 | comment | added | Benjamin Steinberg | I think so. These subgroups still separate points after killing the normal core. | |
| May 19, 2014 at 14:10 | comment | added | Pablo | The chain is assumed to be built of finite index subgroups. The intersection must not be trivial but the largest normal subgroup contained in it may well be trivial. So your method solves it in the general case? After factoring the intersection does not have to become trivial. | |
| May 19, 2014 at 13:27 | comment | added | Benjamin Steinberg | If the chain is finite index then by factoring out by the largest normal subgroup contained in the intersection you can again apply my old argument. | |
| May 19, 2014 at 12:03 | comment | added | Benjamin Steinberg | Are your subgroups in the chain finite index with trivial intersection? If so the proof I gave in your old question works with some minor changes. | |
| May 19, 2014 at 10:12 | history | edited | Pablo | CC BY-SA 3.0 |
added 33 characters in body
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| May 19, 2014 at 10:07 | history | asked | Pablo | CC BY-SA 3.0 |