Timeline for Wait time to grid network disconnection with failing edges
Current License: CC BY-SA 3.0
7 events
when toggle format | what | by | license | comment | |
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May 20, 2014 at 10:33 | vote | accept | Joseph O'Rourke | ||
May 20, 2014 at 4:58 | history | edited | Jan Kyncl | CC BY-SA 3.0 |
now considering also separators formed by two noncontractible curves
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May 20, 2014 at 3:15 | comment | added | Jan Kyncl | You are absolutely right, I missed those disconnected disconnectors; they should be included in the calculations. Fortunately, we have to consider only pairs of boundary curves. Since we are on the torus, at least one of the components of every disconnected subgraph has at most two boundary components (either one contractible curve of a pair of parallel noncontractible curves). | |
May 19, 2014 at 10:41 | comment | added | Joseph O'Rourke | Brilliant idea to use polyomino counts! That leaps the hurdle that was blocking me. However, are there not some non-polyomino disconnectors, e.g., two parallel horizontal rows? Of course their effect would be negligible because they need $2n$ edges to break simultaneously. | |
May 19, 2014 at 7:07 | history | edited | Jan Kyncl | CC BY-SA 3.0 |
added the second sentence, corrected the upper bound
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May 19, 2014 at 6:59 | history | edited | Jan Kyncl | CC BY-SA 3.0 |
added the second sentence
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May 19, 2014 at 1:24 | history | answered | Jan Kyncl | CC BY-SA 3.0 |