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Jul 20, 2014 at 0:14 vote accept CommunityBot
May 19, 2014 at 0:02 comment added Christian Remling $W^2-W'=V-E_0$ has a global solution precisely if $H$ has no spectrum below $E_0$.
May 18, 2014 at 12:06 comment added user37929 great answer, thank you. indeed, such a solution to $W(x)^2-W'(x) = V(x)-E_0$ exists. at least, in some relevant cases.
May 18, 2014 at 12:05 vote accept CommunityBot
May 24, 2014 at 14:32
May 18, 2014 at 10:45 history edited Michael Renardy CC BY-SA 3.0
fixed a typo
May 18, 2014 at 10:17 history answered Carlo Beenakker CC BY-SA 3.0