Timeline for Mathematical equivalent to ladder operators?

Current License: CC BY-SA 3.0

14 events

when toggle format	what		by	license	comment
Jul 20, 2014 at 0:14	vote	accept	CommunityBot
Jul 20, 2014 at 0:14	history	edited	user37929	CC BY-SA 3.0	deleted 1536 characters in body
May 24, 2014 at 20:25	history	edited	user37929	CC BY-SA 3.0	added 14 characters in body
May 24, 2014 at 19:48	answer	added	john mangual		timeline score: -1
May 24, 2014 at 19:18	history	edited	user37929	CC BY-SA 3.0	corrected a few spelling mistakes.
May 24, 2014 at 16:23	history	edited	user37929	CC BY-SA 3.0	added 310 characters in body
May 24, 2014 at 14:27	history	edited	user37929	CC BY-SA 3.0	added 143 characters in body
May 24, 2014 at 14:18	history	edited	user37929	CC BY-SA 3.0	added 1057 characters in body
May 18, 2014 at 14:53	comment	added	Delio Mugnolo		It may be a stupid question, but I don't understand why your operator has discrete spectrum. What happens if $V\equiv 0$? The spectrum of the second derivative on $L^2(I)$ is absolutely continuous if $I=\mathbb R$. Or are you assuming $I$ to be bounded?
May 18, 2014 at 12:05	vote	accept	CommunityBot
May 24, 2014 at 14:32
May 18, 2014 at 10:17	answer	added	Carlo Beenakker		timeline score: 8
May 18, 2014 at 2:47	history	edited	user37929	CC BY-SA 3.0	added 76 characters in body
May 18, 2014 at 2:20	comment	added	S. Carnahan♦		For $V=0$ on $S^1$, you need operators that take $e^{2\pi i n x}$ to $e^{2\pi i (n\pm 1)x}$. In general, it seems that the ladder operators exist, but their explicit form seems to need knowledge of the solutions $\psi_n$. They are generally manifestations of the representation theory of $\mathfrak{su}_2$ or the Heisenberg Lie algebra.
May 18, 2014 at 1:53	history	asked	user37929	CC BY-SA 3.0