Timeline for The order of the discriminant of a good-reduction elliptic curve
Current License: CC BY-SA 2.5
12 events
| when toggle format | what | by | license | comment | |
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| Jan 30, 2011 at 4:56 | answer | added | Chandan Singh Dalawat | timeline score: 1 | |
| Jan 29, 2011 at 13:37 | answer | added | Joe Silverman | timeline score: 8 | |
| Mar 2, 2010 at 4:18 | history | edited | Chandan Singh Dalawat | CC BY-SA 2.5 |
added 25 characters in body
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| Mar 2, 2010 at 2:49 | history | edited | Chandan Singh Dalawat | CC BY-SA 2.5 |
deleted 1 characters in body
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| Mar 2, 2010 at 2:47 | vote | accept | Chandan Singh Dalawat | ||
| Mar 1, 2010 at 17:01 | answer | added | BCnrd | timeline score: 16 | |
| Mar 1, 2010 at 14:01 | history | edited | Chandan Singh Dalawat | CC BY-SA 2.5 |
Addendum.; added 13 characters in body
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| Mar 1, 2010 at 13:51 | comment | added | Chandan Singh Dalawat | You are right : for $p\neq2,3$, you may equivalently think of the question as being about discriminants of elliptic curves over the residue field. | |
| Mar 1, 2010 at 13:31 | comment | added | Qing Liu | Sorry, you are completely right. This bijection with $k^*/{k*}^{12}$ is true only for $p\ne 2,3$. But, if you have an answer over $k$, you have an answer over $K$, and the converse is true if $p\ne 2,3$. | |
| Mar 1, 2010 at 11:24 | comment | added | Chandan Singh Dalawat | I'm a bit worried about the primes 2 and 3. For $K=\mathbb{Q}_2$, the group $\mathbb{F}_2^\times/\mathbb{F}_2^{\times12}$ is trivial, whereas $\mathbb{Z}_2^\times/\mathbb{Z}_2^{\times12}$ is not trivial. | |
| Mar 1, 2010 at 9:56 | comment | added | Qing Liu | Notice that this quantity depends only on the reduction of $E$. So an equivalent form of the question is: if $E$ is an elliptic curve a finite field $k$, what of $E$ is encoded in its discriminant $\in k^*/{k^*}^{12}$ ? | |
| Mar 1, 2010 at 7:01 | history | asked | Chandan Singh Dalawat | CC BY-SA 2.5 |