Timeline for What can we say about the left inverse of the Green's function?
Current License: CC BY-SA 3.0
9 events
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Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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May 16, 2014 at 20:46 | answer | added | Igor Khavkine | timeline score: 3 | |
May 16, 2014 at 19:50 | comment | added | Shiu | This question is motivated by my post on MathStackExchange (please follow the link above). | |
May 16, 2014 at 18:21 | comment | added | k3thomps | Can I ask what you need the left inverse for? It isn't clear to me how it would be useful. | |
May 16, 2014 at 18:16 | history | edited | Shiu | CC BY-SA 3.0 |
self-adjointness added
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May 16, 2014 at 18:15 | comment | added | Shiu | I need self-adjointness. Thank you for pointing out that. I am not sure what to do with the case where $f \not \in \mathrm{Dom}(\mathbb{D})$. This subtlety is part of my question and so I want to understand how to formulate the left inverse. | |
May 16, 2014 at 17:26 | comment | added | k3thomps | You have to be careful. What if $f\notin Domain(\mathbb{D})$? What if $\mathbb{D}$ is not self adjoint (i.e. how do you know that the second integral you wrote down holds true if $\mathbb{D}$ is not self adjoint)? Also, as you pointed out the Fredholm alternative says that you can't solve $\mathbb{D} u = f$ if $f\in ker(\mathbb{D})$. | |
May 16, 2014 at 16:47 | review | First posts | |||
May 16, 2014 at 17:07 | |||||
May 16, 2014 at 16:27 | history | asked | Shiu | CC BY-SA 3.0 |