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Feb 27, 2010 at 20:57 comment added Bill Johnson Mine is maybe more elementary, Anton, but I like yours because it gives more information. Being an analyst, I also prefer path connectness, and I had not realized before reading your argument that you can easily use path connectedness to study spaces that are not path connected. I can see putting this to use on some problems on Lipschitz quotients.
Feb 27, 2010 at 20:51 vote accept HJRW
Feb 27, 2010 at 20:50 comment added Anton Petrunin Your argument is more natural (I simply do not feel comfortable with connected spaces --- path-connected are better).
Feb 27, 2010 at 20:49 comment added Bill Johnson Yes, although by separability you can lower the logical strength a bit if you care about that.
Feb 27, 2010 at 20:46 comment added HJRW I like this. So, Bill, just to be clear, you're invoking Zorn's Lemma to construct your minimal continuum?
Feb 27, 2010 at 20:35 comment added Bill Johnson The intersection of a nested family of continua is again a continuum. You are right to ask about this--it is the only place that compactness is needed.
Feb 27, 2010 at 20:19 comment added LSpice Oops, never mind, I see from above that it is a compact, connected metric space.
Feb 27, 2010 at 20:12 comment added LSpice Bill, I'm sorry to look foolish: What is a continuum here? Is it a set of a certain cardinality, an image of an interval, a connected planar compactum, or something else? (I am no topologist, so I assume that the term is standard; I just haven't encountered it.) The “pass to a minimal sub-continuum” step worries me a little.
Feb 27, 2010 at 20:04 history answered Bill Johnson CC BY-SA 2.5