Skip to main content
10 events
when toggle format what by license comment
May 15, 2014 at 17:00 history closed Michael Zieve
Stefan Kohl
abx
Neil Strickland
Piotr Achinger
Not suitable for this site
May 15, 2014 at 14:46 comment added bananastack @abx: I think it depends on how you define a subscheme. Whenever there is a sheaf $I$ with an injective map $I \to O_X$, I'd like to think of it as an ideal sheaf, regardless of whether it is in fact set-theoretically a subsheaf of $O_X$. If you used the functor of points approach, you might say that a subscheme is a special type of subfunctor, but I'm not sure there is much to gain from that point of view. In the end, isn't it just better to define a subscheme as some $Y$ together with an embedding into $X$?
May 15, 2014 at 9:15 comment added Dubious @abx Yes you are right, this is the point. Two schemes $Y$ and $Y'$ are equal as subschemes of $X$ if they are isomorphic and this isomorphism commutes with two embeddings in $X$
May 15, 2014 at 8:55 comment added abx Two subschemes of a given scheme may, or may not, be equal; "isomorphic subschemes" does not make much sense.
May 15, 2014 at 8:36 review Close votes
May 15, 2014 at 14:42
May 15, 2014 at 7:56 comment added Jérôme Poineau To understand what can go wrong, consider the case of a complex non-real line inside the complex plane.
May 15, 2014 at 7:51 answer added bananastack timeline score: 1
May 15, 2014 at 7:41 history edited Dubious CC BY-SA 3.0
added 5 characters in body
May 15, 2014 at 7:31 history edited Dubious CC BY-SA 3.0
deleted 1 character in body
May 15, 2014 at 7:23 history asked Dubious CC BY-SA 3.0