Timeline for Formula for the Haar measure in the linear symplectic group
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
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| May 13, 2014 at 8:32 | comment | added | alvarezpaiva | @CarloBeenakker: I was referring to the "other" symplectic group (the one preserving the symplectic two-form). | |
| May 13, 2014 at 6:31 | comment | added | Carlo Beenakker | @RobertBryant -- thanks, $n\mapsto i$. | |
| May 13, 2014 at 6:30 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
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| May 12, 2014 at 23:26 | comment | added | Robert Bryant | @CarloBeenakker: A notational point. You seem to be using '$n$' as an index (running over the dimension of the group?). The casual reader might confuse this with the OP's dimensional use of '$n$'. It seems that your answer amounts to the fact that Haar measure is just integration of the density of the bi-invariant pseudo-Riemannian metric on the group. That's true, of course, but it doesn't depend on considering a maximal compact or anything else, other than that the bi-invariant metric on $\mathrm{Sp}(n,\mathbb{R})$ is the restriction of the standard one on $\mathrm{GL}(2n,\mathbb{R})$. | |
| May 12, 2014 at 21:15 | history | edited | Carlo Beenakker | CC BY-SA 3.0 |
added 69 characters in body
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| May 12, 2014 at 20:47 | comment | added | Igor Rivin | Ah, I see the "hyperunitary group". | |
| May 12, 2014 at 20:44 | comment | added | Igor Rivin | What is "the compact symplectic group"? | |
| May 12, 2014 at 20:34 | history | answered | Carlo Beenakker | CC BY-SA 3.0 |