Timeline for Number of binary vectors of a given Hamming weight in a subspace of the Hypercube
Current License: CC BY-SA 3.0
3 events
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May 12, 2014 at 15:23 | comment | added | Anthony Quas | Hmmm... I see... but still you've got $k$ columns with a single 1, leaving only a handful with multiple 1's... Let me think some more... | |
May 12, 2014 at 7:19 | comment | added | Brendan McKay | I don't see why the row-reduced echelon form has at most one 1 in each column. If the first $k$ columns contain an identity matrix, the other columns can have anything at all. | |
May 11, 2014 at 22:16 | history | answered | Anthony Quas | CC BY-SA 3.0 |