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May 12, 2014 at 15:23 comment added Anthony Quas Hmmm... I see... but still you've got $k$ columns with a single 1, leaving only a handful with multiple 1's... Let me think some more...
May 12, 2014 at 7:19 comment added Brendan McKay I don't see why the row-reduced echelon form has at most one 1 in each column. If the first $k$ columns contain an identity matrix, the other columns can have anything at all.
May 11, 2014 at 22:16 history answered Anthony Quas CC BY-SA 3.0