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Apr 5, 2019 at 7:17 comment added user43326 @DavidRoberts thank you for the comment and edit. Actually it was both $H^3$ and $H^5$, I corrected.
Apr 5, 2019 at 7:16 history edited user43326 CC BY-SA 4.0
Corrected $H^3$ missing for $BSO$ case, and removed overlap in $BO$ case.
Apr 5, 2019 at 1:58 vote accept Xiao-Gang Wen
Apr 1, 2019 at 13:15 comment added David Roberts I do wonder if that $H^5$ in the first block, which originally came before the $H^4$ (I re-ordered them in ascending dimension) was meant to be an $H^3$...?
Apr 1, 2019 at 11:44 history edited David Roberts CC BY-SA 4.0
Clean-up
May 9, 2014 at 16:23 history edited user43326 CC BY-SA 3.0
added missed elements pointed out in a comment
May 8, 2014 at 9:29 comment added user43326 You are right, we have $\delta (w_4)$ in $H^5(BSO)$ and $H^5(BO)$, as well as $\delta (w_1)^2$ in $H^4(BO)$. I will edit the answer
May 8, 2014 at 1:16 comment added Xiao-Gang Wen Thank you for the answer. I am not familiar with those polynomial rings. But I wonder do you also have $\delta(w_4)$ term for the $BSO$ and $BO$ cases, and the $\delta(w_1)\delta(w_1)$ for the $BO$ case? May be there are few more $Z/2$'s.
May 7, 2014 at 8:12 history answered user43326 CC BY-SA 3.0