Timeline for when will the surfficient large power of a rational matrix be a integer matrix?
Current License: CC BY-SA 3.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 7, 2014 at 23:51 | comment | added | user9072 | This question appears to be off-topic because it is about a linear algebra problem that is not that compleicated in the end, presented without motivation. | |
| May 7, 2014 at 19:38 | answer | added | David E Speyer | timeline score: 8 | |
| May 7, 2014 at 4:09 | comment | added | Tyler Lawson | Condition (0) is equivalent to the characteristic polynomial of the matrix having integer coefficients (one direction is the Cayley-Hamilton theorem, and the other one can see by showing that $\cup A^k \cdot \Bbb Z^n \subset (\tfrac{1}{M}\Bbb Z)^n$ is finitely generated free and changing basis). | |
| May 7, 2014 at 4:09 | answer | added | The Masked Avenger | timeline score: 3 | |
| May 7, 2014 at 4:08 | comment | added | Gerry Myerson | @Steven, I mostly agree with your comment, but it's not that hard to find an example to show the two conditions are not equivalent. | |
| May 7, 2014 at 2:58 | review | Close votes | |||
| May 8, 2014 at 16:11 | |||||
| May 7, 2014 at 2:53 | review | First posts | |||
| May 7, 2014 at 5:08 | |||||
| May 7, 2014 at 2:46 | comment | added | Steven Landsburg | I don't understand the votes to close (or the downvote). Is there an easy answer I'm not seeing? | |
| May 7, 2014 at 2:42 | comment | added | David Roberts♦ | Is this homework? If so, not on-topic here. | |
| May 7, 2014 at 2:37 | history | asked | user50487 | CC BY-SA 3.0 |